5n^2-16+2n=0

Solution for 5n^2-16+2n=0 equation:

5n^2-16+2n=0

a = 5; b = 2; c = -16;
Δ = b2-4ac
Δ = 22-4·5·(-16)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*5}=\frac{-20}{10}
=-2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*5}=\frac{16}{10}
=1+3/5
$